Python Regex findall But Not Including the conditional string -

i have string:

the quick red fox jumped on lazy brown dog lazy

and wrote regex gives me this:

s = quick red fox jumped on lazy brown dog lazy  re.findall(r'[\s\w\s]*?(?=lazy)', ss)

which gives me below output:

['the quick red fox jumped on ', '', 'azy brown dog ', '']

but trying output this:

['the quick red fox jumped on ']

which means regex should give me till encounters first lazy instead of last 1 , want use findall.

make pattern non-greedy adding ?:

>>> m = re.search(r'[\s\w\s]*?(?=lazy)', s) #                            ^ >>> m.group() 'the quick red fox jumped on '

Tomorrow