javascript - Only allowing form to be submitted if from a certain URL? (iframe, Laravel) -


i'm building service in need people able submit form, through iframe they'd have on own site, need domain listed in user model.

i know possible, need solution whereby users cannot edit js allow work on domain shouldn't (through inspect element etc.).

anyone got solutions? @ appreciated.

you can't access parent page iframe unless both iframe , parent on same domain.


-

Comments

Post a Comment

Popular posts from this blog

php - Auto increment employee ID -

Image
i want add employee , after that, employee id increment. textbox must disabled also here's code. want auto increment employee id when add new employee. hope me. thank in advance. :) <center> <form class="contact_form" action="#" method="post"> <h2>register new employee</h2> <br/> <table> <tr> <td><label for="emp">emp id:</label></td> <td><input type="text" name="emp" placeholder="emp id" required /></td> </tr> <tr> <td><label for="name">name:</label></td> <td><input type="text" name="fname" placeholder="first name" required /> <input type="text" name="lname" placehol...
Read more

php - isset function not working properly -

the page unable see login form code written under isset function statement. have written code correctly , have executed many times , code written inside isset statement not works. here code:- <?php session_start(); echo "<p style=\"font-color: #ff0000;\"> catogoies </p>"; echo '<link href="var/www/html/sample.css" rel="stylesheet">'; require_once('../html/conn.php'); $query = "select * catogories"; mysqli_select_db($dbc, 'odit'); $retrieve = mysqli_query($dbc, $query); if(!$retrieve) { die(mysqli_error($query)); } while($row=mysqli_fetch_array($retrieve, mysql_assoc)){ echo "<p style=\"font-color: #ff0000;\">".'<a href="cats.php? catogory='.urldecode($row["name"]).'">'.$row["name"].'</a>'."</p>"; $_session['cat']=$row["name"]; } if(!($_session)) ...
Read more

python - Evaluating the next line in a For Loop while in the current iteration -

here trying do: trying solve issue has wrapping in text file. i want open txt file, read line , if line contains want contain, check next line see if not contain in first line. if not, add line first line. import re stuff = open("my file") line in stuff: if re.search("from ", line): first = line print first if re.search('from ', handle.next()): continue else: first = first + handle.next() else: continue i have looked quite few things , cannot seem find answer. please help! i try this, invalid triples of "from " , not elegant @ all. lines = open("file", 'r').readlines() lines2 = open("file2", 'w') counter_list=[] last_from = 0 counter, line in enumerate(lines): if "from " in line , counter != last_from +1: last_from = counter current_count = counter if current_coun...
Read more