Comparing nested list Python -

i guess code explain i'm going for...

list1 = [("1", "item 1"), ("2", "item 2"), ("3", "item 3"), ("4", "item 4")] list2 = [("1", "item 1"), ("2", "item 2"), ("4", "item 4")]  newlist = []  i,j in list1:     if not in list2[0]:         entry = (i,j)         newlist.append(entry)  print(newlist) 

if call nested tuples [i][j]

i want compare [i] once has been done want keep corresponding [j] value.

i have found lots of information regarding nested tuples on internet refer finding specific item.

i did use expression below, worked perfectly, seems similar, won't play ball.

for i,j in highscores:     print("\tplayer:\t", j, "\tscore: ", i) 

any apppreciated.

if understand correctly comment take newlist:

newlist = [("3", "item 3")] 

you can using:

1) list comprehension:

newlist = [item item in list1 if item not in list2] print newlist 

this give result:

[('3', 'item 3')] 

2) use symmetric difference like:

l = set(list1).symmetric_difference(list2) newlist = list(l) print newlist 

this give same result!

3) can use lambda function like:

unique = lambda l1, l2: set(l1).difference(l2) x = unique(list1, list2) newlist = list(x) 

this produce same result!

4) oh, , last not least, using simple set properties:

newlist = list((set(list1)-set(list2)))