python - How can I get all media from my own Instagram api? -


i want number of likes each photo or video got. can media count or last 20 of them?

if api access reviewed , approved instagram able more 20 photos using pagination.

check documentation here: https://www.instagram.com/developer/sandbox/


-

Comments

Post a Comment

Popular posts from this blog

javascript - Access directive function from component class or template -

i've got component needs call function in mydirective can't figure out how gain access it, keeps spewing out errors no matter try. i looked @ view child in docs didn't work me, don't show template usage can't sure if i'm doing right. edit: i think it's important note directive imports component, importing directive component seems give circular reference, causing mydirective become undefined if try inject directives:[] part of @component decorator. what need this: component: import {mydirective} 'my-directive.directive'; // shortened example's sake @component({ directives: [mydirective] }) export class { @viewchild(mydirective) mydir: mydirective; } component template: <button (click)="mydir.mydirectivefunc()"></button> what don't want declare mydirective on button because add undesired behavior. want gain access functions. how can this?
Read more

php - Auto increment employee ID -

Image
i want add employee , after that, employee id increment. textbox must disabled also here's code. want auto increment employee id when add new employee. hope me. thank in advance. :) <center> <form class="contact_form" action="#" method="post"> <h2>register new employee</h2> <br/> <table> <tr> <td><label for="emp">emp id:</label></td> <td><input type="text" name="emp" placeholder="emp id" required /></td> </tr> <tr> <td><label for="name">name:</label></td> <td><input type="text" name="fname" placeholder="first name" required /> <input type="text" name="lname" placehol...
Read more

python - Evaluating the next line in a For Loop while in the current iteration -

here trying do: trying solve issue has wrapping in text file. i want open txt file, read line , if line contains want contain, check next line see if not contain in first line. if not, add line first line. import re stuff = open("my file") line in stuff: if re.search("from ", line): first = line print first if re.search('from ', handle.next()): continue else: first = first + handle.next() else: continue i have looked quite few things , cannot seem find answer. please help! i try this, invalid triples of "from " , not elegant @ all. lines = open("file", 'r').readlines() lines2 = open("file2", 'w') counter_list=[] last_from = 0 counter, line in enumerate(lines): if "from " in line , counter != last_from +1: last_from = counter current_count = counter if current_coun...
Read more