Printing numbers from 1-100 as words in Python 3 -

list_of_numbers1to19 = ['one', 'two', 'three', 'four', 'five', 'six', 'seven',                    'eight', 'nine', 'ten', 'eleven', 'twelve', 'thirteen',                    'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen',                    'nineteen'] list_of_numbers1to9 = list_of_numbers1to19[0:9] list_of_numberstens = ['twenty', 'thirty', 'fourty', 'fifty', 'sixty', 'seventy',                        'eighty', 'ninety']  in list_of_numbers1to19:     print(i) list_of_numbers21to99 = [] count = 19 tens_count = 0 j in list_of_numberstens:     k in list_of_numbers1to9:         if tens_count%10 == 0:             #should print iteration of list_of_numberstens             tens_count +=1         tens_count +=1         print(j, k) 

as can see, getting messy :p sorry that. i'm trying print them using 3 different for-loops different index. have tried slicing list , indexing list, keep getting output numbers multipliable 10 full list of list_of_numberstens.

i think it's clear i'm trying here.

thanks in advance help!

i know accepted answer, particularly mentioned nested loops - doesn't use - , you're missing what's great python's iteration , not needing kind of i//10-2 , print(j,k) stuff work out indexes lists.

python's for loop iteration runs on items in list directly , can print them, answer:

digits = ['one', 'two',   'three', 'four', 'five',            'six', 'seven', 'eight', 'nine']  teens  = ['ten', 'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen',            'sixteen', 'seventeen', 'eighteen', 'nineteen']  tens   = ['twenty', 'thirty', 'fourty', 'fifty',            'sixty', 'seventy', 'eighty', 'ninety']  word in digits + teens:     print(word)  tens_word in tens:     print(tens_word)        # e.g. twenty      digits_word in digits:         print(tens_word, digits_word)   # e.g. twenty 1  print("one hundred") 

try online @ repl.it