android - position of ViewPager item with Data Binding -

i have implemented viewpager use of android data binding, working perfect data , click events.

i have created interface click event

public interface itemclicklistener {     public void onitemclick(); } 

here instantiateitem() of pageradapter

@override public object instantiateitem(viewgroup container, final int position) {     listitembinding binding = databindingutil.inflate(mlayoutinflater, r.layout.list_item, container, false);     binding.sethandler(itemclicklistener);     binding.getroot().settag(position);     container.addview(binding.getroot());     return binding.getroot(); } 

i sending itemclicklistener in adapter constructor.

public matchlistadapter(context context, itemclicklistener itemclicklistener) {     mcontext = context;     mlayoutinflater = (layoutinflater) mcontext.getsystemservice(context.layout_inflater_service);     this.itemclicklistener= itemclicklistener; } 

here list_item.xml

<layout xmlns:android="http://schemas.android.com/apk/res/android" xmlns:app="http://schemas.android.com/apk/res-auto">      <data>         <variable            name="handler"            type="com.example.itemclicklistener" />     </data>      <linearlayout         android:id="@+id/root_viewitem"         android:layout_width="match_parent"         android:layout_height="match_parent"         android:onclick="@{() -> handler.onitemclick()}"         android:orientation="vertical">          //rest views , controls.     </linearlayout> </layout> 

now problem want pass position of clicked item, how pass position xml? have called method xml how pass position?

you can pass view in interface

 public interface itemclicklistener {      public void onitemclick(view view);   } 

than set position in tag doing

binding.getroot().settag(position); 

and can position view param this

@override public void onitemclick(view view){   int position=(int)view.gettag(); } 

for more detail info can refer http://developers-club.com/posts/267735/